First, find any solution to (perhaps by using an algorithm listed here); if no such exist, there can be no primitive solution to the original equation. Without loss of generality, we can assume that r0 ≤ m/2 (if not, then replace r0 with m - r0, which will still be a root of -d). Then use the Euclidean algorithm to find , and so on; stop when . If is an integer, then the solution is ; otherwise try another root of -d until either a solution is found or all roots have been exhausted. In this case there is no primitive solution.
To find non-primitive solutions (x, y) where gcd(x, y) = g ≠ 1, note that the existence of such a solution implies that g2 divides m (and equivalently, that if m is square-free, then all solutions are primitive). Thus the above algorithm can be used to search for a primitive solution (u, v) to u2 + dv2 = m/g2. If such a solution is found, then (gu, gv) will be a solution to the original equation.
Example
Solve the equation . A square root of −6 (mod 103) is 32, and 103 ≡ 7 (mod 32); since and , there is a solution x = 7, y = 3.
References
^Cornacchia, G. (1908). "Su di un metodo per la risoluzione in numeri interi dell' equazione ". Giornale di Matematiche di Battaglini. 46: 33–90.