In geometry, two triangles are said to be orthologic if the perpendiculars from the vertices of one of them to the corresponding sides of the other are concurrent (i.e., they intersect at a single point). This is a symmetric property; that is, if the perpendiculars from the vertices A, B, C of triangle △ABC to the sides EF, FD, DE of triangle △DEF are concurrent then the perpendiculars from the vertices D, E, F of △DEF to the sides BC, CA, AB of △ABC are also concurrent. The points of concurrence are known as the orthology centres of the two triangles.[1][2]
Some pairs of orthologic triangles
The following are some triangles associated with the reference triangle ABC and orthologic with it.[3]
The triangle whose vertices are the points of contacts of the excircles with the respective sides of triangle ABC
The triangle formed by the bisectors of the external angles of triangle ABC
The pedal triangle of any point P in the plane of triangle ABC
Theorem on orthologic triangles
Sondat's theorem states that If two triangles ABC and A'B'C' are perspective and orthologic, then the center of perspective P and the orthologic centers Q and Q' are on the same line perpendicular to the axis of perspectivity
[4]: Thm. 1.6