The 1920 Iowa Senate elections took place as part of the biennial 1920 United States elections. Iowa voters elected state senators in 29 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.
A statewide map of the 50 state Senate districts in the 1920 elections is provided by the Iowa General Assembly here.
The primary election on June 7, 1920, determined which candidates appeared on the November 2, 1920 general election ballot.[1][2]
Following the previous election, Republicans had control of the Iowa Senate with 45 seats to Democrats' 5 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 21 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1920 general election with the balance of power shifting to Republicans holding 48 seats and Democrats having 2 seats (a net gain of 3 seats for Republicans).
Source:[3]
District 2 • District 3 • District 4 • District 5 • District 6 • District 8 • District 11 • District 14 • District 15 • District 16 • District 17 • District 19 • District 23 • District 24 • District 25 • District 26 • District 27 • District 28 • District 31 • District 32 • District 33 • District 36 • District 39 • District 40 • District 41 • District 43 • District 46 • District 47 • District 49
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