1902 Minnesota Attorney General election

1902 Minnesota Attorney General election

← 1900 4 November 1902 1904 →
 
Nominee Wallace B. Douglas Frank D. Larrabee
Party Republican Democratic
Popular vote 165,744 90,520
Percentage 64.68% 35.32%

Attorney General before election

Wallace B. Douglas
Republican

Elected Attorney General

Wallace B. Douglas
Republican

The 1902 Minnesota Attorney General election was held on 4 November 1902 in order to elect the attorney general of Minnesota. Republican nominee and incumbent attorney general Wallace B. Douglas defeated Democratic nominee Frank D. Larrabee.[1]

General election

On election day, 4 November 1902, Republican nominee Wallace B. Douglas won re-election by a margin of 75,224 votes against his opponent Democratic nominee Frank D. Larrabee, thereby retaining Republican control over the office of attorney general. Douglas was sworn in for his third term on 7 January 1903.[2]

Results

Minnesota Attorney General election, 1902
Party Candidate Votes %
Republican Wallace B. Douglas (incumbent) 165,744 64.68
Democratic Frank D. Larrabee 90,520 35.32
Total votes 256,264 100.00
Republican hold

References

  1. ^ "Attorney General, 1902 Election". electionarchives.lib.umn.edu. Retrieved 6 October 2024.
  2. ^ "MN Attorney General". ourcampaigns.com. 19 March 2024. Retrieved 6 October 2024.