1870 Rhode Island gubernatorial election

1870 Rhode Island gubernatorial election
← 1869 April 6, 1870 1871 →
 
Nominee Seth Padelford Lyman Pierce
Party Republican Democratic
Popular vote 10,337 6,295
Percentage 62.15% 37.85%

County results
Padelford:      50–60%      60–70%

Governor before election

Seth Padelford
Republican

Elected Governor

Seth Padelford
Republican

The 1870 Rhode Island gubernatorial election took place on April 6, 1870, in order to elect the governor of Rhode Island.[1] Republican candidate and incumbent governor Seth Padelford won his second one-year term as governor[2] over Democratic candidate Lyman Pierce.[3]

Candidates

Election

Statewide

1870 Rhode Island gubernatorial election[1]
Party Candidate Votes %
Republican Seth Padelford 10,337 62.15
Democratic Lyman Pierce 6,295 37.85
Total votes 16,632 100.00
Republican hold

References

  1. ^ a b Dubin, Michael J. (2014). United States Gubernatorial Elections, 1861-1911 | The Official Results by State and County. McFarland. p. 5. ISBN 9780786456468.
  2. ^ a b "Seth Padelford". National Governors Association. 1 January 2019. Retrieved 27 March 2024.
  3. ^ "Our State Election". The Bristol Phoenix. 2 April 1870. Retrieved 27 March 2024 – via NewspaperArchive.com.
  4. ^ "Democratic Nominations". Newport Daily News. 25 March 1869. Retrieved 27 March 2024 – via Newspapers.com.