1998 Franklin Templeton Tennis Classic – Singles
Tennis tournament
1998 tennis event results
Mark Philippoussis was the defending champion, but lost in the second round to Tommy Haas.
Andre Agassi won the title, defeating Jason Stoltenberg 6–4, 7–6(7–3) in the final.[1][2]
Seeds
Draw
Key
Finals
Top half
Bottom half
Qualifying
Qualifying seeds
Qualifiers
Lucky loser
- Scott Draper
Special exempt
- Sébastien Lareau (reached the semifinals at Philadelphia)
Qualifying draw
First qualifier
Second qualifier
Third qualifier
Fourth qualifier
References
External links
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- London (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Singapore (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Marseille (S, D)
- Split (S, D)
- Dubai (S, D)
- St. Petersburg (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- Casablanca (S, D)
- Hong Kong (S, D)
- Estoril (S, D)
- Chennai (S, D)
- Orlando (S, D)
- Prague (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- London/Queen's Club (S, D)
- Bologna (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Los Angeles (S, D)
- Umag (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Boston (S, D)
- Bournemouth (S, D)
- Tashkent (S, D)
- Bucharest (S, D)
- Toulouse (S, D)
- Majorca (S, D)
- Basel (S, D)
- Palermo (S, D)
- Shanghai (S, D)
- Ostrava (S, D)
- Lyon (S, D)
- Mexico City (S, D)
- Bogotá (S, D)
- Santiago (S, D)
- Moscow (S, D)
- Stockholm (S, D)
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Team events | |
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