1992 Wimbledon Championships – Ladies' invitation doubles

Ladies' invitation doubles
1992 Wimbledon Championships
Final
ChampionsAustralia Wendy Turnbull
United Kingdom Virginia Wade
Runners-upUnited States Rosie Casals
United States Sharon Walsh-Pete
Score3–6, 6–3, 7–5
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends men women seniors
← 1991 · Wimbledon Championships · 1993 →
Main article: 1992 Wimbledon Championships

Wendy Turnbull and Virginia Wade defeated Rosie Casals and Sharon Walsh-Pete in the final, 3–6, 6–3, 7–5.

Seeds

  1. Australia Wendy Turnbull / United Kingdom Virginia Wade (champions)
  2. United States Rosie Casals / United States Sharon Walsh-Pete (final)
  3. Australia Lesley Bowrey / Australia Judy Dalton (first round)
  4. France Françoise Dürr / Netherlands Betty Stöve (semifinals)

Draw

Key

Draw

First round Semifinals Final
               
1 Australia Wendy Turnbull
United Kingdom Virginia Wade 		6 6
United States Peggy Michel
United States Yvonne Vermaak 		2 1
1 Australia Wendy Turnbull
United Kingdom Virginia Wade 		6 6
Slovenia Mima Jaušovec
Commonwealth of Independent States Olga Morozova 		3 2
3 Australia Lesley Bowrey
Australia Judy Dalton 		3 3
Slovenia Mima Jaušovec
Commonwealth of Independent States Olga Morozova 		6 6
1 Australia Wendy Turnbull
United Kingdom Virginia Wade 		3 6 7
2 United States Rosie Casals
United States Sharon Walsh-Pete 		6 3 5
Australia Helen Gourlay
United States JoAnne Russell 		6 64 5
4 France Françoise Dürr
Netherlands Betty Stöve 		2 77 7
4 France Françoise Dürr
Netherlands Betty Stöve 		6 2 1
2 United States Rosie Casals
United States Sharon Walsh-Pete 		3 6 6
United Kingdom Lesley Charles
Australia Kerry Reid 		3 3
2 United States Rosie Casals
United States Sharon Walsh-Pete 		6 6