1988 Bordeaux Open – Doubles

Doubles
1988 Bordeaux Open
Final
ChampionsSweden Joakim Nyström
Italy Claudio Panatta
Runners-upArgentina Christian Miniussi
Italy Diego Nargiso
Score6–1, 6–4
Events
Singles Doubles
← 1987 · ATP Bordeaux · 1989 →

Sergio Casal and Emilio Sánchez were the defending champions but none competed this year.

Joakim Nyström and Claudio Panatta won the title by defeating Christian Miniussi and Diego Nargiso 6–1, 6–4 in the final.[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Argentina C Miniussi
Italy D Nargiso
7 6
Italy U Colombini
France L Courteau
6 3 1 Argentina C Miniussi
Italy D Nargiso
7 6
Spain F Luna
Argentina G Rivas
3 3 United States L Duncan
Spain A Tous
6 3
United States L Duncan
Spain A Tous
6 6 1 Argentina C Miniussi
Italy D Nargiso
6 6
3 West Germany P Baur
Brazil L Mattar
7 6 3 West Germany P Baur
Brazil L Mattar
4 4
France T Champion
France É Winogradsky
6 4 3 West Germany P Baur
Brazil L Mattar
7 3 6
Austria T Muster
Austria H Skoff
6 6 Austria T Muster
Austria H Skoff
5 6 3
Morocco K Outaleb
Spain G Urpí
4 2 1 Argentina C Miniussi
Italy D Nargiso
1 4
Peru P Arraya
Spain JC Báguena
7 4 4 2 Sweden J Nyström
Italy C Panatta
6 6
Haiti R Agénor
Morocco Driss Ben Omar
6 6 6 Haiti R Agénor
Morocco Driss Ben Omar
0 4
France S Grenier
Chile M Rodríguez
6 1 6 4 United States B Dickinson
France J Potier
6 6
4 United States B Dickinson
France J Potier
4 6 7 4 United States B Dickinson
France J Potier
4 5
Spain J Arrese
Italy F Cancellotti
6 6 2 Sweden J Nyström
Italy C Panatta
6 7
France JP Fleurian
Italy C Pistolesi
4 1 Spain J Arrese
Italy F Cancellotti
7 1 4
Chile S Cortés
Argentina G Giussani
5 3 2 Sweden J Nyström
Italy C Panatta
5 6 6
2 Sweden J Nyström
Italy C Panatta
7 6

References

  1. ^ "ATP Bordeaux Draw (Men's) - 1988 - Doubles". Steve G Tennis. Retrieved 2 June 2021.