1940 United States presidential election in Delaware

← 1936 November 5, 1940[1] 1944 →
All 3 Delaware votes to the Electoral College
Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York New York Running mate Henry A. Wallace Charles L. McNary Electoral vote 3 0 Popular vote 74,599 61,440 Percentage 54.70% 45.05%
County Results Roosevelt   50-60%
President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Elections in Delaware
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The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (R–New York), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote.^[3][4] Delaware was one of six states that swung more Democratic compared to 1936, alongside Maine, New Hampshire, Rhode Island, Vermont, and North Carolina.

• United States presidential elections in Delaware

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