The 1836 United States presidential election in Arkansas took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election . Voters chose three representatives, or electors to the Electoral College , who voted for President and Vice President .
Arkansas , having been admitted to the Union as the 25th state on June 15, 1836, voted for the Democratic candidate, Martin Van Buren , over Whig candidate Hugh White during its first presidential election. Van Buren won Arkansas by a margin of 28.16%.
Results
Results By County
1836 United States Presidential Election in Arkansas (By County)[ 2]
County
Martin Van Buren
Democratic
Hugh Lawson White
Whig
Total
#
%
#
%
Arkansas
38
31.67%
82
68.33%
120
Carroll
73
92.41%
6
7.59%
79
Chicot
43
45.74%
51
54.26%
94
Clark
41
85.42%
7
14.58%
48
Conway
23
32.39%
48
67.61%
71
Crawford
109
47.81%
119
52.19%
228
Crittenden
38
58.46%
27
41.54%
65
Hempstead
110
56.99%
83
43.01%
193
Hot Spring
11
68.75%
5
31.25%
16
Independence
134
54.25%
113
45.75%
247
Izard
87
85.29%
15
14.71%
102
Jackson
56
53.85%
48
46.15%
104
Jefferson
50
51.02%
48
48.98%
98
Johnson
107
72.79%
40
27.21%
147
Lafayette
30
73.17%
11
26.83%
41
Lawrence
82
72.57%
31
27.43%
113
Monroe
17
32.69%
35
67.31%
52
Phillips
96
59.63%
65
40.37%
161
Pike
33
100.00%
0
0.00%
33
Pope
93
66.91%
46
33.09%
139
Pulaski
234
55.06%
191
44.94%
425
Randolph
138
89.03%
17
10.97%
155
Saline
81
60.90%
52
39.10%
133
Sevier
67
66.34%
34
33.66%
101
St. Francis
108
85.71%
18
14.29%
126
Van Buren
19
67.86%
9
32.14%
28
Washington
622
82.38%
133
17.62%
755
White
17
36.96%
29
63.04%
46
Totals
2,380
64.08%
1,334
35.92%
3,714
See also
References
