Snooker tournament
The 2016 Indian Open was a professional ranking snooker tournament that took place between 5–9 July 2016 at the HICC Novotel Hotel in Hyderabad, India.[1] It was the second ranking event of the 2016/2017 season.[2]
Hyderabad hosted the event for the first time, the previous venue being Grand Hyatt in Mumbai.[1]
Michael White was the defending champion,[3] but he lost 1–4 against Anthony Hamilton in the held over qualifying round.[4]
Anthony McGill won the first ranking title of his career, defeating Kyren Wilson 5–2 in the final.[5]
Prize fund
The breakdown of prize money for this year is shown below:[6]
- Winner: £50,000
- Runner-up: £25,000
- Semi-final: £13,500
- Quarter-final: £9,000
- Last 16: £6,000
- Last 32: £3,000
- Last 64: £2,000
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- Televised highest break: £2,000
- Total: £300,000
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The "rolling 147 prize" for a maximum break stood at £30,000.[7]
Wildcard round
These matches were played in Hyderabad on 5 July 2016.[8][9][10][11]
Main draw
[8][9][10][11]
Final
Qualifying
These matches were held between 28 and 30 May 2016 at the Preston Guild Hall in Preston, England. All matches were best of 7 frames.[10][12][13]
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Interior of the Preston Guild Hall during the qualifying round
- ^ a b Match was held over and played in Hyderabad.
Century breaks
Televised stage centuries
Total: 23[14]
Qualifying stage centuries
Total: 9[15]
References
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| Ranking events | |
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| Non-ranking events | |
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| Amateur events | |
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