Snooker tournament
The 2015 Indian Open was a professional ranking snooker tournament that took place between 10 and 14 March 2015 at the Grand Hyatt in Mumbai , India .[ 1] State Election in Maharashtra .[ 2]
Mumbai played host to the tournament for the first time, having previously being held at the Le Meridien Hotel in New Delhi .[ 3]
Ding Junhui was the defending champion,[ 4] Thepchaiya Un-Nooh in the last 64.[ 5]
Michael White won his first ranking event by defeating Ricky Walden 5–0 in the final.[ 6] [ 7]
Prize fund
The breakdown of prize money for this year is shown below:[ 8]
Winner: £ 50,000
Runner-up: £25,000
Semi-final: £13,500
Quarter-final: £9,000
Last 16: £6,000
Last 32: £3,000
Last 64: £2,000
Wildcard round
These matches were played in Mumbai on 10 March 2015.[ 9] [ 10] [ 11] PYC Hindu Gymkhana in Pune , India .[ 12] [ 13]
Main draw
[ 9] [ 10] [ 11]
Final
Qualifying
These matches were held on 12 and 13 February 2015 at the Barnsley Metrodome in Barnsley , England . The qualifiers were to take place between 18 and 21 September 2014, but were rescheduled as the ranking event was postponed.[ 2] [ 14] [ 15] [ 16]
Century breaks
Qualifying stage centuries
[ 17]
Televised stage centuries
[ 18]
References
