Jefferson, Ohio

Jefferson, Ohio
Village
Ashtabula County Courthouse
Ashtabula County Courthouse
Location of Jefferson, Ohio
Location of Jefferson, Ohio
Location of Jefferson in Ashtabula County
Location of Jefferson in Ashtabula County
Coordinates: 41°44′19″N 80°45′25″W / 41.73861°N 80.75694°W / 41.73861; -80.75694
CountryUnited States
StateOhio
CountyAshtabula
Area
[1]
 • Total2.54 sq mi (6.57 km2)
 • Land2.54 sq mi (6.57 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
[2]
961 ft (293 m)
Population
 (2020)[3]
 • Total3,226
 • Density1,271.58/sq mi (491.04/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
ZIP code
44047
Area code440
FIPS code39-38500[4]
GNIS feature ID1042061[2]
Websitehttps://jeffersonohio.gov/

Jefferson is a village in Ashtabula County, Ohio, United States. The population was 3,226 at the 2020 census.[3] It is the county seat of Ashtabula County.[5]

References

  1. ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. ↑ 2.0 2.1 U.S. Geological Survey Geographic Names Information System: Jefferson, Ohio
  3. ↑ 3.0 3.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson village, Ohio". United States Census Bureau. Retrieved March 16, 2024.
  4. ↑ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  5. ↑ National Association of Counties. "NACo County Explorer". Retrieved March 15, 2024.