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uranium(VIII), corresponding to U+8(B-4–B-4) (same);
uranium(VI), corresponding to U+6(B-3=B-3) (plausible, albeit high oxidation for a boron alloy); or
uranium(IV), corresponding to U+4(B-2≡B-2) (my money's on this one)?
Uranium(II) only makes sense if the boron atoms are connected in a quadruple bond, and there is no evidence of first-row atoms making more than three bonds.
Bernanke's Crossbow (talk) 22:01, 17 July 2023 (UTC)[reply]__DTELLIPSISBUTTON__{"threadItem":{"timestamp":"20230717220100","author":"Bernanke's Crossbow","type":"comment","level":1,"id":"c-Bernanke's_Crossbow-20230717220100-Uranium_diboride","replies":[]}}-->