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Please, define all the terms of the equation. The equation you wrote can only be understood by those who already know it. Defining all the terms is not difficult and it changes everything.

In image sensor spec sheets, it is common to see "responsivity" listed in volts per lux-second. Can anyone explain this in more detail? In particular, I am confused about how this relates to quantum efficiency and to well capacity. My mental model of a pixel is that while it is exposing, photons hit it (that number being related to lux-seconds per pixel area). Those photons then create photoelectrons that get stored in the "well" for that pixel, then the digitization circuitry essentially counts those electrons. Is the potential of those electrons changing as the pixel charges? Is the voltage per lux-second related to the well capacity in any way? For example, if the analog power is 2.8 V, is that the saturation voltage? Could I use V/lux-sec to compute the time it would take a pixel to reach 2.8 V to determine how long it will take to saturate?

Thanks. —Ben FrantzDale (talk) 12:45, 18 June 2013 (UTC)Reply

I share the opinion of Kaajakari[1] and Korvink[2] that sensitivity is the change in output divided by change in input and is the same as responsivity. Further they write that resolution is the minimum signal which can be detected, which is defined here as sensitivity. I think nearly every good scientific book think the same way and I have never read something different.

[1] V. Kaajakari, Practical MEMS

[2] J. G. Korvink and O. Paul, MEMS: A Practical Guide to Design, Analysis, and Applications — Preceding unsigned comment added by 212.114.212.115 (talk) 08:53, 1 July 2016 (UTC)Reply