It is named after English mathematician James Joseph Sylvester. Then given matrices A, B, and C, the problem is to find the possible matrices X that obey this equation. All matrices are assumed to have coefficients in the complex numbers. For the equation to make sense, the matrices must have appropriate sizes, for example they could all be square matrices of the same size. But more generally, A and B must be square matrices of sizes n and m respectively, and then X and C both have n rows and m columns.
A Sylvester equation has a unique solution for X exactly when there are no common eigenvalues of A and −B.
More generally, the equation AX + XB = C has been considered as an equation of bounded operators on a (possibly infinite-dimensional) Banach space. In this case, the condition for the uniqueness of a solution X is almost the same: There exists a unique solution X exactly when the spectra of A and −B are disjoint.[2]
where is of dimension , is of dimension , of dimension and is the identity matrix. In this form, the equation can be seen as a linear system of dimension .[3]
Theorem.
Given matrices and , the Sylvester equation has a unique solution for any if and only if and do not share any eigenvalue.
Proof.
The equation is a linear system with unknowns and the same number of equations. Hence it is uniquely solvable for any given if and only if the homogeneous equation
admits only the trivial solution .
(i) Assume that and do not share any eigenvalue. Let be a solution to the abovementioned homogeneous equation. Then , which can be lifted to
for each
by mathematical induction. Consequently,
for any polynomial . In particular, let be the characteristic polynomial of . Then
due to the Cayley–Hamilton theorem; meanwhile, the spectral mapping theorem tells us
where denotes the spectrum of a matrix. Since and do not share any eigenvalue, does not contain zero, and hence is nonsingular. Thus as desired. This proves the "if" part of the theorem.
(ii) Now assume that and share an eigenvalue . Let be a corresponding right eigenvector for , be a corresponding left eigenvector for , and . Then , and
Hence is a nontrivial solution to the aforesaid homogeneous equation, justifying the "only if" part of the theorem. Q.E.D.
As an alternative to the spectral mapping theorem, the nonsingularity of in part (i) of the proof can also be demonstrated by the Bézout's identity for coprime polynomials.
Let be the characteristic polynomial of . Since and do not share any eigenvalue, and are coprime. Hence there exist polynomials and such that . By the Cayley–Hamilton theorem, . Thus , implying that is nonsingular.
The theorem remains true for real matrices with the caveat that one considers their complex eigenvalues. The proof for the "if" part is still applicable; for the "only if" part, note that both and satisfy the homogenous equation , and they cannot be zero simultaneously.
Roth's removal rule
Given two square complex matrices A and B, of size n and m, and a matrix C of size n by m, then one can ask when the following two square matrices of size n + m are similar to each other: and . The answer is that these two matrices are similar exactly when there exists a matrix X such that AX − XB = C. In other words, X is a solution to a Sylvester equation. This is known as Roth's removal rule.[4]
One easily checks one direction: If AX − XB = C then
Roth's removal rule does not generalize to infinite-dimensional bounded operators on a Banach space.[5] Nevertheless, Roth's removal rule generalizes to the systems of Sylvester equations.[6]
Numerical solutions
A classical algorithm for the numerical solution of the Sylvester equation is the Bartels–Stewart algorithm, which consists of transforming and into Schur form by a QR algorithm, and then solving the resulting triangular system via back-substitution. This algorithm, whose computational cost is arithmetical operations,[citation needed] is used, among others, by LAPACK and the lyap function in GNU Octave.[7] See also the sylvester function in that language.[8][9] In some specific image processing applications, the derived Sylvester equation has a closed form solution.[10]
^However, rewriting the equation in this form is not advised for the numerical solution since this version is costly to solve and can be ill-conditioned.