This article is about the use of a ?: operator as a binary operator. For use as a ternary operator, see ?:.
In certain computer programming languages, the Elvis operator, often written ?:, is a binary operator that returns the evaluated first operand if that operand evaluates to a value likened to logically true (according to a language-dependent convention, in other words, a truthy value), and otherwise returns the evaluated second operand (in which case the first operand evaluated to a value likened to logically false, in other words, a falsy value). This is identical to a short-circuit or with "last value" semantics. The notation of the Elvis operator was inspired by the ternary conditional operator, ? :, since the Elvis operator expression A ?: B is approximately equivalent to the ternary conditional expression A ? A : B.
The name "Elvis operator" refers to the fact that when its common notation, ?:, is viewed sideways, it resembles an emoticon of Elvis Presley with his signature hairstyle.[1]
A similar operator is the null coalescing operator, where the boolean truth(iness) check is replaced with a check for non-null instead. This is usually written ??, and can be seen in languages like C#[2] or Dart.[3]
Alternative syntaxes
In several languages, such as Common Lisp, Clojure, Lua, Object Pascal, Perl, Python, Ruby, and JavaScript, the logical disjunction operator (typically || or or) has the same behavior as the above: returning its first operand if it would evaluate to a truthy value, and otherwise evaluating and returning its second operand, which may be a truthy or falsy value. When the left-hand side is truthy, the right-hand side is not even evaluated; it is "short-circuited". This is different than the behavior in other languages such as C/C++, where the result of || will always be a (proper) boolean.
Example
Boolean variant
In a language that supports the Elvis operator, something like this:
x = f() ?: g()
will set x equal to the result of f() if that result is truthy, and to the result of g() otherwise.
except that it does not evaluate f() twice if it yields truthy. Note the possibility of arbitrary behaviour if f() is not a state-independent function that always returns the same result.
This code will result in a reference to an object that is guaranteed to not be null. Function f() returns an object reference instead of a boolean, and may return null, which is universally regarded as falsy:
x = f() ?: "default value"
Languages supporting the Elvis operator
In GNU C and C++ (that is: in C and C++ with GCC extensions), the second operand of the ternary operator is optional.[4] This has been the case since at least GCC 2.95.3 (March 2001), and seems to be the original Elvis operator.[5]
In Apache Groovy, the "Elvis operator" ?: is documented as a distinct operator;[6] this feature was added in Groovy 1.5[7] (December 2007). Groovy, unlike GNU C and PHP, does not simply allow the second operand of ternary ?: to be omitted; rather, binary ?: must be written as a single operator, with no whitespace in between.
In PHP, it is possible to leave out the middle part of the ternary operator since PHP 5.3.[8] (June 2009).
The Fantom programming language has the ?: binary operator that compares its first operand with null.
In Kotlin, the Elvis operator returns its left-hand side if it is not null, and its right-hand side otherwise.[9] A common pattern is to use it with return, like this: valfoo=bar()?:return
In Gosu, the ?: operator returns the right operand if the left is null as well.
In Ballerina, the Elvis operator L ?: R returns the value of L if it's not nil. Otherwise, return the value of R.[13]
In JavaScript, the nullish coalescing (??) operator is a logical operator that returns its right-hand side operand when its left-hand side operand is null or undefined, and otherwise returns its left-hand side operand.[14]
^Joyce Farrell (7 February 2013). Java Programming. Cengage Learning. p. 276. ISBN978-1285081953. The new operator is called Elvis operator because it uses a question mark and a colon together (?:); if you view it sideways, it reminds you of Elvis Presley.
^"?? Operator". C# Reference. Microsoft. Retrieved 5 December 2018.