Doubles
2018 Boyd Tinsley Clay Court Classic
Final
Champions	Sophie Chang Alexandra Mueller
Runners-up	Ashley Kratzer Whitney Osuigwe
Score	3–6, 6–4, [10–7]
Events
Singles Doubles
← 2017 · Boyd Tinsley Clay Court Classic · 2019 →

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

	First round							Quarterfinals							Semifinals							Final
	1	I Bara M Duque Mariño	6	6
		K Cartwright K Pierre-Louis	3	1				1	I Bara M Duque Mariño	2	7	[10]
	WC	A Smith N Subhash	6	6				WC	A Smith N Subhash	6	5	[5]
		M Mateas R Yurovsky	2	4											1	I Bara M Duque Mariño	6	4	[4]
	3	S Chang A Mueller	6	6											3	S Chang A Mueller	1	6	[10]
		L Chirico F Di Lorenzo	3	3				3	S Chang A Mueller	7	6
		P Januskova R Ozaki	4	6	[7]				C Rosatello AS Sánchez	5	2
		C Rosatello AS Sánchez	6	3	[10]																	3	S Chang A Mueller	3	6	[10]
		V Duval J Loeb	6	4	[10]																		A Kratzer W Osuigwe	6	4	[7]
		Q Gleason A Weinhold	2	6	[8]				V Duval J Loeb	6	62	[10]
		A Kratzer W Osuigwe	6	6					A Kratzer W Osuigwe	3	77	[12]
	4	PC Gonçalves S Marand	3	4												A Kratzer W Osuigwe	6	2	[12]
		J Cristian K Day	1	3												I Neel M Sanchez	4	6	[10]
		I Neel M Sanchez	6	6					I Neel M Sanchez	6	1	[20]
		R McAdoo K Stewart	6	4	[7]			2	A Guarachi E Routliffe	2	6	[18]
	2	A Guarachi E Routliffe	2	6	[10]

• Main Draw