2015 Challenger Banque Nationale de Saguenay – Doubles

Doubles
2015 Challenger Banque Nationale de Saguenay
Final
ChampionsRomania Mihaela Buzărnescu
Poland Justyna Jegiołka
Runners-upCanada Sharon Fichman
United States Maria Sanchez
Score7–6(8–6), 4–6, [10–7]
Events
Singles Doubles
← 2014 · Challenger de Saguenay · 2016 →

Ysaline Bonaventure and Nicola Slater were the defending champions, but decided not to participate this year.

Mihaela Buzărnescu and Justyna Jegiołka won the title, defeating Sharon Fichman and Maria Sanchez 7–6(8–6), 4–6, [10–7] in the final.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 Canada S Fichman
United States M Sanchez
6 6
Oman F Al-Nabhani
India KK Thandi
0 1 1 Canada S Fichman
United States M Sanchez
7 6
Canada M-A Leduc
Canada C Robillard-Millette
77 6 Canada M-A Leduc
Canada C Robillard-Millette
5 0
Serbia J Jakšić
United States M Oudin
65 3 1 Canada S Fichman
United States M Sanchez
6 6
3 United States A Weinhold
United States C Whoriskey
6 6 3 United States A Weinhold
United States C Whoriskey
3 0
Germany K Grajdek
United States E Halbauer
2 3 3 United States A Weinhold
United States C Whoriskey
6 6
WC Canada R Cruickshank
Canada S Peterson-Paul
1 3 Mexico S León
United States J Pegula
2 1
Mexico S León
United States J Pegula
6 6 1 Canada S Fichman
United States M Sanchez
66 6 [7]
Romania M Buzărnescu
Poland J Jegiołka
6 6 Romania M Buzărnescu
Poland J Jegiołka
78 4 [10]
WC Canada P Januskova
Canada A Wozniak
4 3 Romania M Buzărnescu
Poland J Jegiołka
1 6 [10]
Germany A Lottner
Switzerland A Sadiković
4 3 4 Belgium M Benoît
United States S Crawford
6 4 [5]
4 Belgium M Benoît
United States S Crawford
6 6 Romania M Buzărnescu
Poland J Jegiołka
3 77 [10]
WC Canada I Boulais
Canada M Drake
3 2 Netherlands Q Lemoine
Netherlands E Wacanno
6 64 [6]
United States K Ahn
Hungary F Stollár
6 6 United States K Ahn
Hungary F Stollár
4 6 [8]
Netherlands Q Lemoine
Netherlands E Wacanno
7 6 Netherlands Q Lemoine
Netherlands E Wacanno
6 4 [10]
2 Czech Republic B Krejčíková
Canada C Zhao
5 4

References