1996 Marbella Open – Doubles
1996 tennis event results
Tomás Carbonell and Francisco Roig were the defending champions but were defeated in the quarterfinals by Pablo Albano and Lucas Arnold.
Andrew Kratzmann and Jack Waite won in the final 6–7, 6–3, 6–4 against Albano and Arnold.[1]
Seeds
Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.
Draw
Key
References
External links
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Milan (S, D)
- Philadelphia (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart Outdoor (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Auckland (S, D)
- Jakarta (S, D)
- Sydney (S, D)
- Shanghai (S, D)
- Zagreb (S, D)
- Dubai (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Mexico City (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- St. Petersburg (S, D)
- Casablanca (S, D)
- Estoril (S, D)
- Hong Kong (S, D)
- New Delhi (S, D)
- Bermuda (S, D)
- Seoul (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Prague (S, D)
- Pinehurst (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- London/Queen's Club (S, D)
- Oporto (S, D)
- Rosmalen (S, D)
- Bologna (S, D)
- Halle (S, D)
- Nottingham (S, D)
- Båstad (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- Los Angeles (S, D)
- San Marino (S, D)
- Umag (S, D)
- Long Island (S, D)
- Bogotá (S, D)
- Bournemouth (S, D)
- Bucharest (S, D)
- Basel (S, D)
- Palermo (S, D)
- Lyon (S, D)
- Marbella (S, D)
- Singapore (S, D)
- Beijing (S, D)
- Ostrava (S, D)
- Tel Aviv (S, D)
- Toulouse (S, D)
- Moscow (S, D)
- Santiago (S, D)
- Stockholm (S, D)
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Team events | |
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