1993 Romanian Open – Doubles

Doubles
1993 Romanian Open
Final
ChampionsNetherlands Menno Oosting
Belgium Libor Pimek
Runners-upRomania George Cosac
Romania Ciprian Petre Porumb
Score7–6, 7–6
Details
Draw16 (1WC/1Q)
Seeds4
Events
Singles Doubles
Romanian Open · 1994 →

In the first edition of the tournament, Menno Oosting and Libor Pimek won the title by defeating George Cosac and Ciprian Petre Porumb 7–6, 7–6 in the final.[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Netherlands M Oosting
Belgium L Pimek
3 7 7
Italy C Brandi
Italy A Gaudenzi
6 5 5 1 Netherlands M Oosting
Belgium L Pimek
6 1 7
Australia J Ireland
United States J Yancey
3 3 Argentina J Garat
Argentina R Saad
4 6 6
Argentina J Garat
Argentina R Saad
6 6 1 Netherlands M Oosting
Belgium L Pimek
4 7 6
3 United States D Johnson
United States K Kinnear
6 4 6 Q Czech Republic T Krupa
Czech Republic P Vízner
6 5 2
Latvia Ģ Dzelde
Finland O Rahnasto
3 6 7 Latvia Ģ Dzelde
Finland O Rahnasto
2 6 1
Q Czech Republic T Krupa
Czech Republic P Vízner
7 3 6 Q Czech Republic T Krupa
Czech Republic P Vízner
6 4 6
Spain J Arrese
Spain F Roig
6 6 3 1 Netherlands M Oosting
Belgium L Pimek
7 7
Romania D Pescariu
Austria H Skoff
6 6 WC Romania G Cosac
Romania CP Porumb
6 6
Sweden J Donar
Sweden O Jonsson
4 4 Romania D Pescariu
Austria H Skoff
6 2
WC Romania G Cosac
Romania CP Porumb
6 6 WC Romania G Cosac
Romania CP Porumb
7 6
4 Sweden R Båthman
Czech Republic V Flégl
4 1 WC Romania G Cosac
Romania CP Porumb
3 6 7
Sweden N Holm
Sweden N Utgren
1 6 6 Netherlands M Schapers
Czech Republic D Vacek
6 3 6
Sweden C Allgårdh
Sweden T Nydahl
6 4 7 Sweden C Allgårdh
Sweden T Nydahl
6 6 3
Netherlands M Schapers
Czech Republic D Vacek
7 6 Netherlands M Schapers
Czech Republic D Vacek
7 4 6
2 United States M Bauer
Argentina H de la Peña
6 4

References

  1. ^ "Tennis 24: ATP Bucharest Doubles 1993 Results". Tennis 24. Retrieved 23 March 2023.