Pana Tinani Island

Nickname: Joannett Island
Pana Tinani Island
Geography
Location	Oceania=
Coordinates	11°13′48″S 153°09′32″E / 11.23000°S 153.15889°E / -11.23000; 153.15889[1]
Archipelago	Louisiade Archipelago
Adjacent to	Solomon Sea
Total islands	1
Major islands	Pana Tinani
Area	78 km2 (30 sq mi)
Length	19 km (11.8 mi)
Width	6 km (3.7 mi)
Highest elevation	338 m (1109 ft)
Highest point	Mount Guyuba
Administration
Papua New Guinea
Province	Milne Bay
District	Samarai-Murua District
LLG[2]	Yaleyamba Rural Local Level Government Area
Island Group	Pana Tinani Group
Largest settlement	Bwailahina (pop. ~200)
Demographics
Population	740 (2014)
Pop. density	9.5/km2 (24.6/sq mi)
Ethnic groups	Papauans, Austronesians, Melanesians.
Additional information
Time zone	AEST (UTC+10)
ISO code	PG-MBA
Official website	www.ncdc.gov.pg

Pana Tinani is an island in the Louisiade Archipelago in Milne Bay Province, Papua New Guinea.

The island has an area of 78 km² (30 sq mi), making it the sixth largest island of the Louisiade Archipelago. The island is hilly, rising to 338 m (1,109 ft) at Mt. Guyuba. The island is 3.1 km (1.9 mi) north of Vanatinai, and separated from it with the Bulami Channel. It is also 100 meters (330 ft) east of Nigao, the easternmost island in the Calvados Chain. separated with the Magamaga Channel.

The island was discovered in the late 18th century, named after the wife of the explorer Joannett.

At the census of population in 2014, the island had 740 inhabitants, spread across 11 villages. The main town is Bwailahina (formerly Hebwaun) on the southeast coast. The island's population is administered by 2 wards : Nimoa Ward, Wanim Ward.

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