Township in Indiana, United States
Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2020 census, its population was 1,551 and it contained 690 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]
Historical population
Census | Pop. | Note | %± |
1890 | 1,495 | | — |
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1900 | 1,675 | | 12.0% |
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1910 | 1,603 | | −4.3% |
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1920 | 1,522 | | −5.1% |
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1930 | 1,430 | | −6.0% |
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1940 | 1,220 | | −14.7% |
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1950 | 1,410 | | 15.6% |
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1960 | 1,621 | | 15.0% |
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1970 | 1,629 | | 0.5% |
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1980 | 1,810 | | 11.1% |
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1990 | 1,641 | | −9.3% |
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2000 | 1,694 | | 3.2% |
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2010 | 1,581 | | −6.7% |
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2020 | 1,551 | | −1.9% |
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Geography
According to the 2020 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]
Cities and towns
Unincorporated towns
Adjacent townships
Major highways
Cemeteries
The township contains two cemeteries: Justus and Oxford.
References
Citations
Sources
External links