Exhaustion by compact sets

In mathematics, especially general topology and analysis, an exhaustion by compact sets[1] of a topological space is a nested sequence of compact subsets of (i.e. ), such that each is contained in the interior of , i.e. , and .

A space admitting an exhaustion by compact sets is called exhaustible by compact sets.[2]

As an example, for the space , the sequence of closed balls forms an exhaustion of the space by compact sets.

There is a weaker condition that drops the requirement that is in the interior of , meaning the space is σ-compact (i.e., a countable union of compact subsets.)

Construction

If there is an exhaustion by compact sets, the space is necessarily locally compact (if Hausdorff). The converse is also often true. For example, for a locally compact Hausdorff space that is a countable union of compact subsets, we can construct an exhaustion as follows. We write as a union of compact sets . Then inductively choose open sets with compact closures, where . Then is a required exhaustion.

For a locally compact Hausdorff space that is second-countable, a similar argument can be used to construct an exhaustion.

Application

For a Hausdorff space , an exhaustion by compact sets can be used to show the space is paracompact.[3] Indeed, suppose we have an increasing sequence of open subsets such that and each is compact and is contained in . Let be an open cover of . We also let . Then, for each , is an open cover of the compact set and thus admits a finite subcover . Then is a locally finite refinement of

Remark: The proof in fact shows that each open cover admits a countable refinement consisting of open sets with compact closures and each of whose members intersects only finitely many others.[3]

The following type of converse also holds. A paracompact locally compact Hausdorff space with countably many connected components is a countable union of compact sets[4] and thus admits an exhaustion by compact subsets.

Relation to other properties

The following are equivalent for a topological space :[5]

  1. is exhaustible by compact sets.
  2. is σ-compact and weakly locally compact.
  3. is Lindelöf and weakly locally compact.

(where weakly locally compact means locally compact in the weak sense that each point has a compact neighborhood).

The hemicompact property is intermediate between exhaustible by compact sets and σ-compact. Every space exhaustible by compact sets is hemicompact[6] and every hemicompact space is σ-compact, but the reverse implications do not hold. For example, the Arens-Fort space and the Appert space are hemicompact, but not exhaustible by compact sets (because not weakly locally compact),[7] and the set of rational numbers with the usual topology is σ-compact, but not hemicompact.[8]

Every regular Hausdorff space that is a countable union of compact sets is paracompact.[citation needed]

Notes

  1. ^ Lee 2011, p. 110.
  2. ^ Harder 2011, Definition 4.4.10.
  3. ^ a b Warner 1983, Ch. 1. Lemma 1.9.
  4. ^ Wall, Proposition A.2.8. (ii) NB: the proof in the reference looks problematic. It can be fixed by constructing an open cover whose member intersects only finitely many others. (Then we use the fact that a locally finite connected graph is countable.)
  5. ^ "A question about local compactness and $\sigma$-compactness". Mathematics Stack Exchange.
  6. ^ "Does locally compact and $\sigma$-compact non-Hausdorff space imply hemicompact?". Mathematics Stack Exchange.
  7. ^ "Can a hemicompact space fail to be weakly locally compact?". Mathematics Stack Exchange.
  8. ^ "A $\sigma$-compact but not hemicompact space?". Mathematics Stack Exchange.

References