De Soto, Nebraska

De Soto, Nebraska
Map
Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W / 41.5011528; -96.0567083
CountryUnited States
StateNebraska
CountyWashington
Elevation
[1]
1,007 ft (307 m)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
Area code402

De Soto is an unincorporated community in Washington County, Nebraska, United States.[1] It was named in honor of the sixteenth-century Spanish explorer, Hernando De Soto.[2] De Soto was founded in 1855 and served as the county seat from 1858-1866. During its heyday, the town hosted many flourishing new businesses: hotels, saloons, stores, newspapers and banks.[3]

De Soto contains farmland with about three families residing there.[4]

References

  1. ^ a b U.S. Geological Survey Geographic Names Information System: De Soto, Nebraska
  2. ^ Hernando De Soto[usurped]
  3. ^ "DeSoto Townsite - Washington County Historical Association". Archived from the original on October 11, 2008. Retrieved June 24, 2008.
  4. ^ Kancoll.org


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