2005 Welsh Open (snooker)
Snooker tournament
The 2005 Welsh Open was a professional ranking snooker tournament that took place between 17 and 23 January 2005 at the Newport Centre in Newport, Wales.
Ronnie O'Sullivan successfully defended his title by beating Stephen Hendry 9–8.
Tournament summary
Defending champion and World Champion Ronnie O'Sullivan was the number 1 seed. The remaining places were allocated to players based on the world rankings.
Prize fund
The breakdown of prize money for this year is shown below:[1]
- Winner: £35,000
- Runner-up: £17,500
- Semi-final: £8,750
- Quarter-final: £6,500
- Last 16: £4,275
- Last 32: £2,750
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- Last 48: £1,725
- Last 64: £1,325
- Highest break: £2,000
- Maximum break: £20,000
- Total: £225,000
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Main draw
[2][3][4]
Final
Final: Best of 17 frames. Referee: Colin Brinded. Newport Centre, Newport, Wales, 23 January 2005.[2]
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Ronnie O'Sullivan (1) England
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9–8
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Stephen Hendry (3) Scotland
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Afternoon: 0–96 (92), 42–74 (67), 69–55 (62), 0–140 (140), 72–65 (O'Sullivan 59, Hendry 57), 72–22, 60–30, 41–70 (69) Evening: 0–93 (93), 122–0 (102), 50–74, 0–71 (57), 106–0 (75), 108–6 (52), 132–0 (131), 8–71, 68–0 (67)
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131
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Highest break
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140
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2
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Century breaks
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1
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7
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50+ breaks
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7
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Qualifying
Qualifying for the tournament took place at Pontin's in Prestatyn, Wales between 7 January and 9 January 2005.[3]
Century breaks
[3]
Qualifying stage centuries
Televised stage centuries
- 146, 133, 131, 127, 126, 114, 110, 102, 102, 101 – Ronnie O'Sullivan
- 140, 128, 125, 119, 119, 103 – Stephen Hendry
- 138, 117 – Ali Carter
- 133 – Ken Doherty
- 132 – Joe Perry
- 129 – Drew Henry
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References
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Non-ranking events | |
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