1998 International Tennis Championships – Doubles
1998 tennis event results
Dave Randall and Greg Van Emburgh were the defending champions, but did not participate together this year. Randall partnered Jean-Philippe Fleurian, losing in the first round. Van Emburgh partnered Geoff Grant, losing in the first round.
Grant Stafford and Kevin Ullyett won in the final 7–5, 6–4, against Mark Merklein and Vincent Spadea.
Seeds
Draw
Key
Draw
External links
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- London (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Singapore (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Marseille (S, D)
- Split (S, D)
- Dubai (S, D)
- St. Petersburg (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- Casablanca (S, D)
- Hong Kong (S, D)
- Estoril (S, D)
- Chennai (S, D)
- Orlando (S, D)
- Prague (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- London/Queen's Club (S, D)
- Bologna (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Los Angeles (S, D)
- Umag (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Boston (S, D)
- Bournemouth (S, D)
- Tashkent (S, D)
- Bucharest (S, D)
- Toulouse (S, D)
- Majorca (S, D)
- Basel (S, D)
- Palermo (S, D)
- Shanghai (S, D)
- Ostrava (S, D)
- Lyon (S, D)
- Mexico City (S, D)
- Bogotá (S, D)
- Santiago (S, D)
- Moscow (S, D)
- Stockholm (S, D)
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Team events | |
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