1998 Family Circle Cup – Doubles
1998 tennis event results
Mary Joe Fernández and Martina Hingis were the defending champions but did not compete that year.
Conchita Martínez and Patricia Tarabini won in the final 3–6, 6–4, 6–4 against Lisa Raymond and Rennae Stubbs .
Seeds
Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.
Draw
Key
Final
Top half
First round
Second round
Quarterfinals
Semifinals
1
6
6
Q
6
6
Q
0
1
2
3
1
1
4
6
6
7
6
6
WC
1
2
7
0
3
2
1
7
5
6
6
7
6
6
7
7
7
5
5
5
3
6
6
7
6
1
4
6
1
3
2
4
6
5
6
5
6
6
3
7
1
3
6
4
2
6
5
6
2
6
5
6
7
Bottom half
First round
Second round
Quarterfinals
Semifinals
6
7
6
6
3
6
6
6
7
6
1
3
6
1
6
6
6
WC
6
3
6
WC
4
4
4
6
4
WC
7
6
4
5
3
6
7
6
8
4
6
4
2
6
4
6
2
6
w/o
2
2
6
6
1
2
6
5
2
6
6
7
7
4
6
1
2
6
4
6
External links
Grand Slam events Tier I tournaments Tier II tournaments
Sydney (S , D )
Paris (S , D )
Hanover (S , D )
Linz (S , D )
Amelia Island (S , D )
Hamburg (S , D )
Eastbourne (S , D )
Stanford (S , D )
San Diego (S , D )
Los Angeles (S , D )
New Haven (S , D )
Tokyo (S , D )
Filderstadt (S , D )
Leipzig (S , D )
Philadelphia (S , D )
Tier III tournaments
Gold Coast (S , D )
Oklahoma City (S , D )
Tokyo Outdoor (S , D )
Strasbourg (S , D )
Madrid (S , D )
Birmingham (S , D )
Rosmalen (S , D )
Prague (S , D )
Warsaw (S , D )
Boston (S , D )
Quebec City (S , D )
Luxembourg (S , D )
Tier IV tournaments
Auckland (S , D )
Hobart (S , D )
Bogotá (S , D )
Makarska (S , D )
Budapest (S , D )
Bol (S , D )
Maria Lankowitz (S , D )
Palermo (S , D )
Sopot (S , D )
Istanbul (S , D )
Pattaya City (S , D )
Team events