Doubles
1989 Virginia Slims of Indianapolis
Final
Champions	Katrina Adams Lori McNeil
Runners-up	Claudia Porwik Larisa Savchenko
Score	6–4, 6–4
Details
Draw	16
Seeds	4
Events
Singles Doubles
← 1988 · Virginia Slims of Indianapolis · 1990 →

Larisa Savchenko and Natasha Zvereva were the defending champions, but Zvereva chose to compete at Worcester during the same week.

Savchenko teamed up with Claudia Porwik and lost in the final to Katrina Adams and Lori McNeil. The score was 6–4, 6–4.^[1]

	First round							Quarterfinals							Semifinals							Final
	1	K Adams L McNeil	6	6
		R Baranski P Vásquez	3	3				1	K Adams L McNeil	6	6
		J Mundel G Purdy	6	4	0				S Foltz P Thorén	3	2
		S Foltz P Thorén	4	6	6										1	K Adams L McNeil	6	6	6
	3	M Bollegraf K Maleeva	6	6											3	M Bollegraf K Maleeva	7	2	3
		S Amiach H Witvoet	4	3				3	M Bollegraf K Maleeva	4	6	6
		L Antonoplis G Miró	2	5					K Foxworth T Whittington	6	1	1
		K Foxworth T Whittington	6	7																		1	K Adams L McNeil	6	6
		H Na R Reis	6	7	7																	2	C Porwik L Savchenko	4	4
		H Cioffi A Frazier	7	5	6				H Na R Reis	4	6	5
		A Grousbeck M Norwood	2	3				4	N Medvedeva L Meskhi	6	3	7
	4	N Medvedeva L Meskhi	6	6											4	N Medvedeva L Meskhi	6	6	4
		C Lindqvist J Pospíšilová	4	3											2	C Porwik L Savchenko	7	2	6
		M Lindström H Ludloff	6	6					M Lindström H Ludloff	3	4
		D Faber J Thomas	1	6	6			2	C Porwik L Savchenko	6	6
	2	C Porwik L Savchenko	6	3	7

• Official results archive (ITF)
• Official results archive (WTA)